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Chapter 4: Measurement of Matter

Solved textbook questions with step-by-step explanations.

Grade 9 Q&A: Chapter 4: Measurement of Matter

Grade 9 Q&A: Chapter 4: Measurement of Matter

Welcome to the Questions and Answers section for Grade 9 Science, Chapter 4: "Measurement of Matter." This chapter covers the fundamental laws governing chemical reactions, the concepts of atoms, molecules, valency, and the mole, which is essential for quantitative chemistry. We will also learn how to write chemical formulae and calculate molecular masses.

Important Questions and Answers

Q1: State the Law of Conservation of Mass.

Answer: The Law of Conservation of Mass, proposed by Antoine Lavoisier, states that in any chemical reaction, the total mass of the reactants is equal to the total mass of the products. Mass is neither created nor destroyed during a chemical reaction.

Q2: State the Law of Constant Proportions.

Answer: The Law of Constant Proportions, proposed by J.L. Proust, states that in a chemical compound, the constituent elements are always present in definite proportions by mass, regardless of the source or method of preparation. For example, in water (H₂O), the ratio of the mass of hydrogen to the mass of oxygen is always 1:8.

Q3: What is an atom? What determines the mass of an atom?

Answer: An atom is the smallest particle of an element that retains the chemical properties of that element. The mass of an atom is primarily concentrated in its nucleus, which contains protons and neutrons. The atomic mass is approximately the sum of the number of protons and neutrons.

Q4: What is meant by atomic mass unit (u)?

Answer: The atomic mass unit (u), also known as the unified atomic mass unit or Dalton (Da), is a standard unit used to express atomic and molecular masses. Currently, 1 u is defined as one-twelfth (1/12) the mass of a single neutral atom of Carbon-12 (¹²C) in its ground state. 1 u ≈ 1.660539 × 10⁻²⁷ kg.

Q5: Define valency.

Answer: Valency is the combining capacity of an element or a radical. It represents the number of electrons an atom can donate, accept, or share to form chemical bonds with other atoms. It is typically represented as a positive integer.

Q6: What are molecules?

Answer: Molecules are the smallest particles of an element or a compound that can exist independently under ordinary conditions and show all the properties of that substance. They are formed when two or more atoms bond together chemically (e.g., O₂, H₂O, CO₂).

Q7: Define molecular mass.

Answer: The molecular mass of a substance is the sum of the atomic masses of all the atoms present in one molecule of that substance. It is expressed in atomic mass units (u).

Q8: How do you calculate the molecular mass of a compound? Give an example for water (H₂O).

Answer: To calculate the molecular mass, you multiply the atomic mass of each element by the number of its atoms in the molecule and then add these values together.
Example for Water (H₂O):
Atomic mass of Hydrogen (H) = 1 u
Atomic mass of Oxygen (O) = 16 u
Molecular mass of H₂O = (Number of H atoms × Atomic mass of H) + (Number of O atoms × Atomic mass of O)
= (2 × 1 u) + (1 × 16 u)
= 2 u + 16 u
= 18 u

Q9: What is the mole concept?

Answer: The mole concept relates the mass of a substance to the number of particles (atoms, molecules, ions) it contains. A mole is a unit used to measure the amount of substance.

Q10: Define one mole.

Answer: One mole (mol) of any substance is defined as the amount of that substance which contains the same number of particles (atoms, molecules, ions, etc.) as there are atoms in exactly 12 grams of Carbon-12 (¹²C). This number is known as Avogadro's number.

Q11: What is Avogadro's number? What is its value?

Answer: Avogadro's number (N<0xE2><0x82><0x90>) is the number of constituent particles (usually atoms or molecules) that are contained in one mole of a substance. Its accepted value is approximately 6.022 × 10²³ particles per mole.

Q12: How are moles, mass, and number of particles related?

Answer:

  1. Moles and Mass: The mass of one mole of a substance in grams is numerically equal to its atomic mass (for elements) or molecular mass (for compounds). This is called the molar mass (grams/mol).
    Number of moles (n) = Given mass (m) / Molar mass (M)
  2. Moles and Number of Particles: One mole of any substance contains Avogadro's number (N<0xE2><0x82><0x90>) of particles.
    Number of particles = Number of moles (n) × Avogadro's number (N<0xE2><0x82><0x90>)

Q13: Calculate the number of moles in 36 g of water (H₂O).

Answer:
First, find the molar mass of water (H₂O).
Molecular mass of H₂O = (2 × 1) + 16 = 18 u.
Therefore, the molar mass of H₂O = 18 g/mol.
Given mass (m) = 36 g.
Number of moles (n) = Given mass (m) / Molar mass (M)
n = 36 g / 18 g/mol = 2 mol.
There are 2 moles in 36 g of water.

Q14: How many molecules are present in 66 g of CO₂?

Answer:
First, find the molar mass of CO₂.
Atomic mass of C = 12 u, Atomic mass of O = 16 u.
Molecular mass of CO₂ = 12 + (2 × 16) = 12 + 32 = 44 u.
Molar mass of CO₂ = 44 g/mol.
Number of moles (n) = Given mass / Molar mass = 66 g / 44 g/mol = 1.5 mol.
Number of molecules = Number of moles × Avogadro's number (N<0xE2><0x82><0x90>)
= 1.5 × 6.022 × 10²³
= 9.033 × 10²³ molecules.
There are 9.033 × 10²³ molecules in 66 g of CO₂.

Q15: What are radicals (ions)?

Answer: Radicals, also known as ions, are atoms or groups of atoms that carry a positive or negative charge due to the loss or gain of electrons. Positively charged ions are called cations, and negatively charged ions are called anions.

Q16: Differentiate between simple radicals and compound radicals.

Answer:

  • Simple Radicals (Monoatomic ions): These consist of a single atom carrying a charge (e.g., Na⁺, Mg²⁺, Cl⁻, O²⁻).
  • Compound Radicals (Polyatomic ions): These consist of a group of two or more atoms bonded together that collectively carry a charge (e.g., SO₄²⁻ (sulfate), NH₄⁺ (ammonium), OH⁻ (hydroxide)).

Q17: What are acidic and basic radicals?

Answer: In the context of salts formed from acids and bases:

  • Acidic Radicals (Anions): These are negatively charged ions derived from acids (e.g., Cl⁻ from HCl, SO₄²⁻ from H₂SO₄, NO₃⁻ from HNO₃).
  • Basic Radicals (Cations): These are positively charged ions derived from bases (e.g., Na⁺ from NaOH, Ca²⁺ from Ca(OH)₂, NH₄⁺ from NH₄OH).

Q18: What is variable valency? Give an example.

Answer: Some elements exhibit more than one valency in different compounds. This property is called variable valency. Examples include:

  • Iron (Fe): Shows valency 2 (Fe²⁺, ferrous) and 3 (Fe³⁺, ferric).
  • Copper (Cu): Shows valency 1 (Cu⁺, cuprous) and 2 (Cu²⁺, cupric).
  • Mercury (Hg): Shows valency 1 (Hg₂²⁺, mercurous) and 2 (Hg²⁺, mercuric).

Q19: What are the steps to write the chemical formula of a compound?

Answer:

  1. Step 1: Write the symbols of the constituent radicals (cation first, then anion).
  2. Step 2: Write the valency below each respective radical.
  3. Step 3: Cross-multiply the valencies to get the number of atoms/radicals. Write these numbers as subscripts. (Ignore charges during cross-multiplication). Simplify the subscripts to the simplest whole number ratio if possible.
  4. Step 4: Write the final chemical formula. If a subscript is 1, it is omitted. If a compound radical needs a subscript greater than 1, enclose the radical in parentheses before writing the subscript.

Q20: Write the chemical formula for Sodium Sulfate.

Answer:
1. Symbols: Na (Sodium), SO₄ (Sulfate)
2. Valencies: Na (1), SO₄ (2)
3. Cross-multiply: Na gets 2, SO₄ gets 1
4. Formula: Na₂SO₄

Q21: Write the chemical formula for Aluminum Hydroxide.

Answer:
1. Symbols: Al (Aluminum), OH (Hydroxide)
2. Valencies: Al (3), OH (1)
3. Cross-multiply: Al gets 1, OH gets 3.
4. Formula: Al(OH)₃ (Parentheses needed for the compound radical OH).

Q22: Write the chemical formula for Ferric Oxide.

Answer:
Ferric indicates Iron (Fe) with valency 3.
Oxide indicates Oxygen (O) with valency 2.
1. Symbols: Fe, O
2. Valencies: Fe (3), O (2)
3. Cross-multiply: Fe gets 2, O gets 3.
4. Formula: Fe₂O₃

Q23: Calculate the molecular mass of Sulphuric Acid (H₂SO₄).

Answer:
Atomic mass H = 1 u, S = 32 u, O = 16 u.
Formula: H₂SO₄
Molecular mass = (2 × Atomic mass of H) + (1 × Atomic mass of S) + (4 × Atomic mass of O)
= (2 × 1 u) + (1 × 32 u) + (4 × 16 u)
= 2 u + 32 u + 64 u
= 98 u

Q24: Calculate the molecular mass of Calcium Chloride (CaCl₂).

Answer:
Atomic mass Ca = 40 u, Cl = 35.5 u.
Formula: CaCl₂
Molecular mass = (1 × Atomic mass of Ca) + (2 × Atomic mass of Cl)
= (1 × 40 u) + (2 × 35.5 u)
= 40 u + 71 u
= 111 u

Q25: What is the mass of 0.5 moles of Nitrogen gas (N₂)?

Answer:
First, find the molar mass of Nitrogen gas (N₂).
Atomic mass of N = 14 u.
Molecular mass of N₂ = 2 × 14 u = 28 u.
Molar mass of N₂ = 28 g/mol.
Number of moles (n) = 0.5 mol.
Mass (m) = Number of moles (n) × Molar mass (M)
m = 0.5 mol × 28 g/mol
m = 14 g

Q26: How many atoms are there in 1 mole of Sodium (Na)?

Answer: One mole of any element contains Avogadro's number of atoms. Therefore, 1 mole of Sodium (Na) contains 6.022 × 10²³ atoms.

Q27: Name the cation and anion in the compound MgCl₂.

Answer:
Cation (positive ion): Mg²⁺ (Magnesium ion)
Anion (negative ion): Cl⁻ (Chloride ion)

Q28: Deduce the valency of Cu in CuO and Cu₂O.

Answer:
Oxygen (O) typically has a valency of 2 (O²⁻).
* In CuO: Let the valency of Cu be x. Total charge = 0. x + (-2) = 0 => x = +2. Valency of Cu is 2 (Cupric).
* In Cu₂O: Let the valency of Cu be y. (2 × y) + (-2) = 0 => 2y = 2 => y = +1. Valency of Cu is 1 (Cuprous).

Q29: What information is conveyed by the chemical formula of a compound?

Answer: The chemical formula of a compound conveys:

  1. The types of elements present in the compound.
  2. The number of atoms of each element present in one molecule (or formula unit) of the compound.
  3. The ratio in which atoms of different elements combine.
  4. It allows calculation of the molecular mass (or formula mass) of the compound.

Q30: Why is it important to know the valencies of elements and radicals?

Answer: Knowing the valencies is crucial for correctly writing the chemical formulae of compounds. The valencies determine the ratio in which atoms or radicals combine to form electrically neutral compounds, following the principle of charge balance (total positive valency = total negative valency).

Exercise Solutions

Q1: Give examples.

  1. Positive radicals (Cations)
    Answer: Na⁺, K⁺, Ca²⁺, Mg²⁺, Al³⁺, NH₄⁺, Fe²⁺, Fe³⁺, Cu⁺, Cu²⁺.
  2. Basic radicals (Cations)
    Answer: Same as positive radicals: Na⁺, K⁺, Ca²⁺, Mg²⁺, Al³⁺, NH₄⁺.
  3. Composite radicals (Polyatomic ions)
    Answer: SO₄²⁻ (Sulfate), CO₃²⁻ (Carbonate), OH⁻ (Hydroxide), NO₃⁻ (Nitrate), NH₄⁺ (Ammonium).
  4. Metals with variable valency
    Answer: Iron (Fe: +2, +3), Copper (Cu: +1, +2), Mercury (Hg: +1, +2), Tin (Sn: +2, +4).
  5. Bivalent acidic radicals (Anions with valency 2)
    Answer: SO₄²⁻ (Sulfate), CO₃²⁻ (Carbonate), S²⁻ (Sulfide), O²⁻ (Oxide).
  6. Trivalent basic radicals (Cations with valency 3)
    Answer: Al³⁺ (Aluminum ion), Fe³⁺ (Ferric ion).

Q2: Write symbols of the following elements and the radicals obtained from them, and indicate the charge on the radicals.

ElementSymbolRadical SymbolCharge
MercuryHgHg²⁺ / Hg₂²⁺+2 / +1
PotassiumKK⁺+1
NitrogenNN³⁻ (Nitride)-3
CopperCuCu⁺ / Cu²⁺+1 / +2
SulphurSS²⁻ (Sulfide)-2
CarbonCC⁴⁺ / C⁴⁻ *+4 / -4 *
ChlorineClCl⁻ (Chloride)-1
OxygenOO²⁻ (Oxide)-2

*Note: Carbon usually forms covalent bonds. Simple ions are rare.

Q3: Write the steps in deducing the chemical formulae of the following compounds.

  1. Sodium sulphate
    Steps: 1. Symbols: Na, SO₄. 2. Valencies: Na(1), SO₄(2). 3. Cross-multiply: Na₂, (SO₄)₁. 4. Formula: Na₂SO₄.
  2. Potassium nitrate
    Steps: 1. Symbols: K, NO₃. 2. Valencies: K(1), NO₃(1). 3. Cross-multiply: K₁, (NO₃)₁. 4. Formula: KNO₃.
  3. Ferric phosphate
    Steps: 1. Symbols: Fe(III), PO₄. 2. Valencies: Fe(3), PO₄(3). 3. Cross-multiply & simplify: Fe₃(PO₄)₃ -> Fe₁(PO₄)₁. 4. Formula: FePO₄.
  4. Calcium oxide
    Steps: 1. Symbols: Ca, O. 2. Valencies: Ca(2), O(2). 3. Cross-multiply & simplify: Ca₂O₂ -> Ca₁O₁. 4. Formula: CaO.
  5. Aluminium hydroxide
    Steps: 1. Symbols: Al, OH. 2. Valencies: Al(3), OH(1). 3. Cross-multiply: Al₁, (OH)₃. 4. Formula: Al(OH)₃.

Q4: Write answers to the following questions and explain your answers.

  1. Explain how the element sodium is monovalent.
    Answer: Sodium (Na, Atomic No. 11) has electronic configuration 2, 8, 1. It readily loses its single valence electron to achieve a stable octet, forming Na⁺ ion. Since it loses 1 electron, its valency is 1, making it monovalent.
  2. M is a bivalent metal. Write down the steps to find the chemical formulae of its compounds formed with the sulphate and phosphate radicals.
    Answer: M is bivalent (M²⁺). Sulphate is SO₄²⁻ (valency 2). Phosphate is PO₄³⁻ (valency 3).
    With Sulphate: Symbols M, SO₄; Valencies 2, 2; Cross-multiply & simplify M₂ (SO₄)₂ -> M₁ (SO₄)₁; Formula: MSO₄.
    With Phosphate: Symbols M, PO₄; Valencies 2, 3; Cross-multiply M₃ (PO₄)₂; Formula: M₃(PO₄)₂.
  3. Explain the need for a reference atom for atomic mass.
    Answer: Absolute masses of atoms are extremely small. A reference atom (Carbon-12, assigned exactly 12 u) allows for a relative scale (atomic mass units, u), making it practical to compare and calculate atomic and molecular masses based on experimental ratios.
  4. What is meant by ‘Unified Atomic Mass’?
    Answer: Unified Atomic Mass Unit (u) or Dalton (Da) is 1/12th the mass of a neutral Carbon-12 atom. It's the standard unit for expressing atomic and molecular masses on a relative scale.
  5. Explain with examples what is meant by ‘a mole’ of a substance.
    Answer: A mole (mol) is an amount of substance containing Avogadro's number (6.022 × 10²³) of particles (atoms/molecules/ions). The mass of one mole in grams (molar mass) is numerically equal to the substance's atomic/molecular mass in u.
    Examples: 1 mol of C atoms = 12.01 g = 6.022 × 10²³ C atoms. 1 mol of H₂O molecules = 18.02 g = 6.022 × 10²³ H₂O molecules.

Q5: Write the names of the following compounds and deduce their molecular masses.

(Atomic masses: H=1, O=16, Na=23, Mg=24, Al=27, S=32, Cl=35.5, K=39, Ca=40, N=14)

  1. NaOH: Sodium Hydroxide. Mass = 23 + 16 + 1 = 40 u.
  2. MgO: Magnesium Oxide. Mass = 24 + 16 = 40 u.
  3. AlCl₃: Aluminum Chloride. Mass = 27 + (3 × 35.5) = 27 + 106.5 = 133.5 u.
  4. Ca(OH)₂: Calcium Hydroxide. Mass = 40 + 2 × (16 + 1) = 40 + 34 = 74 u.
  5. H₂SO₄: Sulphuric Acid. Mass = (2 × 1) + 32 + (4 × 16) = 2 + 32 + 64 = 98 u.
  6. KNO₃: Potassium Nitrate. Mass = 39 + 14 + (3 × 16) = 39 + 14 + 48 = 101 u.

Q6: Two samples ‘m’ and ‘n’ of slaked lime [Ca(OH)₂] ... Which law of chemical combination does this prove? Explain.

Answer: Law of Constant Proportions.
Explanation: Calculate the ratio of mass of Ca to mass of O in each sample.
Sample m: Ca:O = 5g : 2g = 2.5 : 1.
Sample n: Ca:O = 1.0g : 0.4g = 10:4 = 2.5 : 1.
Since the ratio of masses of constituent elements (Ca and O) is constant (2.5:1) in both samples obtained differently, it proves the Law of Constant Proportions.

Q7: Deduce the number of molecules of the following compounds in the given quantities.

(Avogadro’s number = 6.022 x 10²³)

  1. 32 g Oxygen (O₂): Molar mass O₂ = 32 g/mol. Moles = 32g / 32g/mol = 1 mol. Molecules = 1 × 6.022 × 10²³ = 6.022 × 10²³.
  2. 90 g Water (H₂O): Molar mass H₂O = 18 g/mol. Moles = 90g / 18g/mol = 5 mol. Molecules = 5 × 6.022 × 10²³ = 3.011 × 10²⁴.
  3. 8.8 g Carbon dioxide (CO₂): Molar mass CO₂ = 44 g/mol. Moles = 8.8g / 44g/mol = 0.2 mol. Molecules = 0.2 × 6.022 × 10²³ = 1.2044 × 10²³.
  4. 7.1 g Chlorine (Cl₂): Molar mass Cl₂ = 71 g/mol. Moles = 7.1g / 71g/mol = 0.1 mol. Molecules = 0.1 × 6.022 × 10²³ = 6.022 × 10²².

Q8: If 0.2 mol of the following substances are required, how many grams of those substances should be taken?

  1. Sodium chloride (NaCl): Molar mass = 58.5 g/mol. Mass = 0.2 mol × 58.5 g/mol = 11.7 g.
  2. Magnesium oxide (MgO): Molar mass = 40 g/mol. Mass = 0.2 mol × 40 g/mol = 8.0 g.
  3. Calcium carbonate (CaCO₃): Molar mass = 100 g/mol. Mass = 0.2 mol × 100 g/mol = 20.0 g.

References

  1. Maharashtra State Board Science and Technology Standard Nine Textbook (Latest Edition) - Chapter 4: Measurement of Matter.
  2. Maharashtra State Board 9th Standard Science Syllabus.
  3. Balbharati Science and Technology Textbook Part 1.